Multiplication and Division (Class 3)

What this worksheet covers

This is a fifteen-question practice worksheet on multiplication and division for Class 3, written to the pattern of the SOF International Mathematics Olympiad (IMO). It carries 21 marks and is designed to be attempted in 40 minutes, split across three sections — Mathematical Reasoning, Everyday Mathematics and Reasoning and Achievers Section. Every question is multiple choice with exactly one correct option, and every one comes with a fully worked solution rather than just an answer key — so a child who gets one wrong can see where the reasoning went astray instead of only learning that it did.

Skills your child practises

• Applied problem-solving on multiplication and division at Class 3 level
• Working accurately against a time limit, as the real paper demands
• Mathematical Reasoning questions in the olympiad format
• Everyday Mathematics and Reasoning questions in the olympiad format
• Achievers Section questions in the olympiad format
• Reading worked solutions to find the step that went wrong

How to use it

1. 1There are 15 questions in this worksheet. All questions are compulsory.
2. 2Each question has four options (A), (B), (C) and (D). Exactly one option is correct.
3. 3Questions 1–12 carry 1 mark each. Questions 13–15 (Achievers Section) carry 3 marks each.
4. 4There is no negative marking. Use of a calculator is not allowed.
5. 5Rough work may be done in the space at the side of each page.

Sample questions from this worksheet

A preview of what's inside Multiplication and Division (Class 3) — the PDF has the full set, and every question comes with a worked solution like these.

1. 1. 24 × 3 = _______

   • A27
   • B62
   • C72correct
   • D82
   Solution: Ones: 4 × 3 = 12, write 2 and carry 1.
   Tens: 2 × 3 = 6, plus the carried 1 makes 7.
   Answer = 72.

2. 2. A box holds 15 chocolates. How many chocolates are there in 8 such boxes?

   • A23
   • B110
   • C120correct
   • D130
   Solution: 8 boxes × 15 chocolates each.
   15 × 8 = 120 chocolates.

3. 3. A shopkeeper buys 6 cartons of soap. Each carton has 24 bars. He sells 100 bars. How many bars are left?

   • A24
   • B44correct
   • C144
   • D244
   Solution: First find the total: 6 × 24 = 144 bars.
   Then subtract what he sold: 144 − 100 = 44 bars left.