Maths Full Practice Exam – Set 2 (Class 5)

What this worksheet covers

This is a 50-question practice worksheet on full practice exam — set 2 for Class 5, written to the pattern of the SOF International Mathematics Olympiad (IMO). It carries 60 marks and is designed to be attempted in 60 minutes, split across four sections — Section 1 — Logical Reasoning, Section 2 — Mathematical Reasoning, Section 3 — Everyday Mathematics and Achievers Section. Every question is multiple choice with exactly one correct option, and every one comes with a fully worked solution rather than just an answer key — so a child who gets one wrong can see where the reasoning went astray instead of only learning that it did.

Skills your child practises

• Applied problem-solving on full practice exam — set 2 at Class 5 level
• Working accurately against a time limit, as the real paper demands
• Section 1 — Logical Reasoning questions in the olympiad format
• Section 2 — Mathematical Reasoning questions in the olympiad format
• Section 3 — Everyday Mathematics questions in the olympiad format
• Achievers Section questions in the olympiad format
• Reading worked solutions to find the step that went wrong

How to use it

1. 1There are 50 questions in this paper. All questions are compulsory.
2. 2Each question has four options (A), (B), (C) and (D). Exactly one option is correct.
3. 3Questions 1–45 carry 1 mark each. Questions 46–50 (Achievers Section) carry 3 marks each.
4. 4There is no negative marking. Use of a calculator is not allowed.
5. 5Fill in your answers on the answer sheet. Rough work may be done at the side of each page.

Sample questions from this worksheet

A preview of what's inside Maths Full Practice Exam – Set 2 (Class 5) — the PDF has the full set, and every question comes with a worked solution like these.

1. 1. What comes next in the series? 5, 10, 20, 40, ____

   • A60
   • B70
   • C80correct
   • D90
   Solution: Each number is doubled to get the next: 5, 10, 20, 40, and 40 × 2 = 80.

2. 2. What is the place value of 7 in 3,74,829?

   • A7,000
   • B700
   • C7,00,000
   • D70,000correct
   Solution: The digit 7 sits in the ten thousands place, so its place value is 7 × 10,000 = 70,000.

3. 3. A toy costs ₹235. Karan buys 3 such toys and pays with a ₹1,000 note. How much change does he get?

   • A₹295correct
   • B₹765
   • C₹305
   • D₹235
   Solution: Cost of 3 toys = 3 × 235 = ₹705.
   Change = 1,000 − 705 = ₹295.